The first set:
3x + 2y = 2 ---1)
5x + 4y = 6 ---2)
From 1), multiply all by 2, 6x + 4y = 4 ---3)
3) - 2),
6x + 4y - (5x + 4y) = 6 - 4
6x + 4y - 5x - 4y = 2
x = 2
Sub in x = 2 into 1),
3(2) + 2y = 2
2y = -4
y = -2
(2 , -2)
The second set:
3x + 2y = 2 ---1)
11x + 8y = 10 ---2)
From 1), multiply all by 4, 12x + 8y = 8 ---3)
3) - 2),
12x + 8y - (11x + 8y) = 8 - 10
12x + 8y - 11x - 8y = -2
x = -2
From this x value alone, we can tell that these two linear systems do NOT have the same solution as they meet at different coordinates.
Hope this helped! Ask me if there's any working from here that you don't understand! :)
Answer:
see explanation
Step-by-step explanation:
The diagonals of a parallelogram bisect each other , then
CO = OA = b
DO = OB = a
(a)
CA = CO + OA = b + b = 2b
(b)
DC = DO + OC = a - b
(c)
CB = CO + OB = b + a = a + b
Answer:
0.8686 or 86.86 %
0.2148 or 21.48 %
Step-by-step explanation:
In z table the value of z > - 1,12 is 0.1314 (value from the z point to the left of the curve ) then 1 - 01314 will be value from z point to the right
Again from z table we get for z = - 0.79 the value 0.2148 s the vale from the point up to the left tail
that is unsolvable coz no double decimal can be used
