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xxTIMURxx [149]

2 years ago

13

Please help me! The i is an imaginary number (9+4i)^2

1 answer:

beks73 [17]2 years ago

4 0

Answer: 2500

Explanation: I turned the I into a 1 and it turned into a 41 so I added 9+41 which is 50. Then I multiplied 50 by 50 because of the ^2 which gave me 2500. I’m assuming that you can put whatever number as a replacement for the I. I’m sorry if this answer isn’t right.

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Answer:

12

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likoan [24]

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4 years ago

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Harman [31]

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8 0

3 years ago

Solve for y<br> 2(3 + 3y) + y = 11

garik1379 [7]

<h2><u>EQUATION</u></h2><h3>Exercise</h3>

2(3 + 3y) + y = 11

First, apply the distributive property:

2(3 + 3y) + y = 11

6 + 6y + y = 11

6 + 7y = 11

Substract 6 from both sides:

6 - 6 + 7y = 11 - 6

7y = 5

Divide both sides by 7:

$\dfrac{7y}{7} = \dfrac{5}{7}$

$\boxed{y = \dfrac{5}{7}}$

<h3><u>Answer</u>. The value of y = 5/7.</h3>

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