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nika2105 [10]
3 years ago
8

How would you simplify 5-6w-4+7w?

Mathematics
1 answer:
Natasha2012 [34]3 years ago
6 0
You add the like terms. In this case, the like terms are -6w,+7w & 5,-4.
-6w + 7w = 1w.
5 - 4 = -1.
The coefficients (terms with variables - letters) comes firm, then the terms (numbers) 
.
so the final answer is: 1w -1   :)
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Angles A and B are complementary. What is the value of x? 34 56 68 79
Lelu [443]

Answer: x = 34°


Explanation:


As per definition, complementary angles add up 90°.


In the figure you see angle A measures x + 22° and angle B measures x.


Therefore, according to the definition, you can set this equation:

       

             x + 22° + x = 90°


Solve for x:


  • start: x + 22 + x = 90
  • combine like terms: 2x + 22 = 90
  • subraction property: 2x = 90 - 22
  • do the operation: 2x = 68
  • division propery: x = 68/2
  • do the operation: x = 34

Answer: x = 34°

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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vladimir1956 [14]

Answer:

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Step-by-step explanation:

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If
arlik [135]

Given:

In a right angle triangle θ is an acute angle and \tan\theta =\dfrac{3}{5}.

To find:

The value of \cos \theta.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

We have,

\tan\theta =\dfrac{3}{5}

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

Hypotenuse=\sqrt{Perpendicular^2+base^2}

Hypotenuse=\sqrt{(3x)^2+(5x)^2}

Hypotenuse=\sqrt{9x^2+25x^2}

Hypotenuse=\sqrt{34x^2}

Hypotenuse=x\sqrt{34}

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

\cos \theta=\dfrac{5x}{x\sqrt{34}}

\cos \theta=\dfrac{5}{\sqrt{34}}

Therefore, the value of \cos \theta is \dfrac{5}{\sqrt{34}}.

8 0
3 years ago
I don't understand this question
padilas [110]

Answer:

105 rooms

Step-by-step explanation:

quarter=1/4

total rooms=140

rooms cleaned=1/4×140=35

140-35=105

therefore total rooms remaining are 105 rooms

hopes this helps

brainliest pls

7 0
2 years ago
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