(-5, 12). Cosecant is the reciprocal of sine. Since csc theta =13/12, sin theta=12/13. We can narrow down to two angles, one in first quadrant and one in second quadrant. We are also given sec theta=-13/5, so cos theta=-5/13. Thus the angle is in the second quadrant. tan theta=1/cot theta=-12/5, so point (-5, 12) is on the ray.
Y=5x
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-denis
Answer: x=3 and y=−2
Step-by-step explanation:
x=−2y−1;4x−4y=20
Step: Solve x=−2y−1 for x:
Step: Substitute−2y−1 for x in 4x−4y=20:
4x−4y=20
4(−2y−1)−4y=20
−12y−4=20(Simplify both sides of the equation)
−12y−4+4=20+4(Add 4 to both sides)
−12y=24
−12y
−12
=
24
−12
(Divide both sides by -12)
y=−2
Step: Substitute−2 for y x=−2y−1:
x=−2y−1
x=(−2)(−2)−1
x=3(Simplify both sides of the equation)
Answer:
14
Step-by-step explanation:
Hypotenuse^2=base^2+perp^2
50^2=base^2+48^2
2500-2304=base^2
Base^2=196
Taking sq root
Base=14
Answer:
The system has exactly one solution where x = 0 and y = -3.
Step-by-step explanation:
-6x + y = -3
7x - y = 3
(7x - 6x) + (y - y) = 3 - 3
x + 0 = 0
x = 0
7(0) - y = 3
0 - y = 3
-y = 3
y = -3
-6(0) + y = -3
0 + y = -3
y = -3
So, the system has exactly one solution where x = 0 and y = -3.
Hope this helps!
