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2 years ago

8

In order for you to answer the question correctly, please use the following image down below:

1 answer:

adell [148]2 years ago

7 0

Answer:

36

Step-by-step explanation:

24^2 = (12)(12+x)

576 = 144 + 12x

432 = 12x

36 = x

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Based on the line plot, how many batteries lasted more than 5 1/2 hours? *

babunello [35]

Answer:

5 batteries.

Explanation:

"How many batteries lasted more than 5 1/2 hours?" which means it's counting not only 5 1/2, but 5 3/4 and 6 1/4

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3 years ago

Read 2 more answers

If Joey had 5,000,000 dollars and spent 28% of the money, how much will he have left?

Mrac [35]

Answer:

3600000

Step-by-step explanation:

5000000*.28 = 1400000

5000000-1400000 = 3600000

5 0

2 years ago

A taxi driver determines the fare using the formula F=1.50+2.6m, where F is the total fare and m id the numbet a miles driven. W

Lady bird [3.3K]

Just do 1.50 + 2.6(3.5)

The answer is $10.60

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3 years ago

HELP ASAP WITH THIS QUESTION

alexgriva [62]

Hey there (again)

$x = 2y \\ y = -2 \\ x = 2(-2) \\x= -4 \\ \\ \\ w + xy + 4x^2 = 2\\ w+-4(-2) + 3(-4)^2 = 2 \\ w + 8 + 3(16) = 2 \\ w + 8 + 48 = 2 \\ Subtract56: w + 56 =2 \\ 56 - 56 (Cancel) \\ 2 - 56 = -54 \\ w = -54$

Answer: $B$ the simplification performed in step 2 is invalid or incorrect

Good luck on your assignment and enjoy your day

~ $MeIsKaitlyn:)$

5 0

3 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

2 years ago