The given sequence is
a₁, a₂, ...,

Because the given sequence is an arithmetic progression (AP), the equation satisfied is

where
d = the common difference.
The common difference may be determined as
d = a₂ - a₁
The common difference is the difference between successive terms, therefore
d = a₃ - a₂ = a₄ - a₃, and so on..
The sum of the first n terms is

Example:
For the arithmetic sequence
1,3,5, ...,
the common difference is d= 3 - 1 = 2.
The n-th term is

For example, the 10-term is
a₁₀ = 1 + (10-1)*2 = 19
Th sum of th first 10 terms is
S₁₀ = (10/2)*(1 + 19) = 100
Answer:
4x^2 + 4x + 1=9
4x^2 + 4x - 8=0
Dividing both sides by 4
x^2 + x -2=0
It can be written as
x^2 + 2x - x - 2=0
x(x+2) -1(x+2)=0
taking (x+2) as common on LHS
Then, (x+2)(x-1)=0
Now first equate x+2=0 ie x=-2
then x-1=0 ie x=1
Therefore, x has two values(roots)
that is -2,1
<span>0.05 is 10 times greater than 0.005</span>
Square root (x + 8) -6 = x
square root (x + 8) = x -6
x^2 + 16x + 64 = x^2 -12x + 36
28x = 48
x =
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1.7142857143
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None of the above
The third one is the smallest