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3 years ago

Calculate the mean of the number set 5 10 12 4 6 11 13 5

1 answer:

3 0

For calculating the mean, you want to add up all of the numbers then divide by how many numbers there are. So you'd do:

5+10+12+4+6+11+13+5 then divide that by 8

The answer to your question is: 8.25

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6x minus 2y equals 24

Drupady [299]

Answer:

slope:-3 y-intercept 12

6 0

3 years ago

Rajan needs 1 liter of 15% hydrochloric acid solution for an experiment. He checks his storage cabinet, but he only has a 5-lite

Delvig [45]

Answer:

0.75 liters of 5% hydrochloric acid solution
0.25 liters of 45% hydrochloric acid solution.

Step-by-step explanation:

Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.

As Rajan need total of 1 liter of solution, so

$x+y=1$

i.e $x=1-y$ --------------------1

As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

$0.05x+0.45y=1\times 0.15$

i.e $5x+45y=15$ -------------2

Putting value of x from equation 1 in equation 2,

$\Rightarrow 5(1-y)+45y=15$

$\Rightarrow 5-5y+45y=15$

$\Rightarrow 5+40y=15$

$\Rightarrow 40y=15-5=10$

$\Rightarrow y=0.25$

Putting the value of y in equation 1,

$x=1-0.25=0.75$

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters of 45% hydrochloric acid solution.

4 0

4 years ago

A class is made up of 8 boys and 8 girls

rodikova [14]

Hello,

The answer is "8:8 or 1".

Reason:

There are 8 boys and 8 girls therefore the ratio would be...

8:8

8:8=1

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

3 0

3 years ago

A) how many ways are there to choose 10 players to take the field?

Kruka [31]

A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

possible choices.

5 0

4 years ago

Factor the expression using the common factor −6 . −12x−18y−3.6 Drag a value or operation/sign to the boxes to correctly factor

Sphinxa [80]

Answer: 2 2 3 4 5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers