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jarptica [38.1K]

3 years ago

12

An auditorium has three levels. Level 1 seats 3,577 people, Level 2 seats 5,214 people, and Level 3 seats 5,879 people. How many

seats are in all three levels combined? A. 8,991 B. 14,670 C. 14,970 D. 14,370

1 answer:

galben [10]3 years ago

7 0

Answer:

14,670

Step-by-step explanation:

3,577 + 5,214 + 5,879 =14,670. Hope this helps! ☺

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Ber [7]

A)
8^2+9^2=c^264+81=c^2
c^2=145c=sqrt 145c=12.04
B)
Pythagerean Theorum:
A^2+B^2=C^2, where C is the hypotenuse and A and B are the other legs
15^2=9^2+B^2
225=81+B^2
225-81=B^2
144=B^2 (square root both sides)
12=B

5 0

3 years ago

What is the total area of the prism?

Pavlova-9 [17]

First we look for the area of the triangle which is given by:
A = (1/2) * (4) * (6)
A = 12 feet ^ 2
Area of the rectangles:
Rectangle 1:
R1 = (4) * (8)
R1 = 32 feet ^ 2
Rectangle 2:
R2 = (6) * (8)
R2 = 48 feet ^ 2
Rectangle 3:
R3 = (root (6 ^ 2 + 4 ^ 2)) * (8))
R3 = 57,68882041 feet ^ 2
The total area will be:
A = 2A + R1 + R2 + R3
Substituting values:
A = 2 * (12) + 32 + 48 + 57,68882041
A = 161.6888204 feet ^ 2
Answer:
The total area of the prism is:
A = 161.6888204 feet ^ 2

6 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

HELP PLEASE!Write the equation of the line parallel to y = –x + 5 passing through the point (9, –1).

Westkost [7]

Y=-x+8
gradient of the parallel line is the same as the gradient of the line given, which is -1
to find the y-intercept, sub the values (9,-1) into the equation we are finding which is y=-x+c

5 0

3 years ago

(2x - 3y + 1) + (4x + y + 5)=

disa [49]

6x-2y+5. Here you just do addition/subtraction with the coefficients on the variables.

3 0

3 years ago