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s344n2d4d5 [400]
3 years ago
7

20. How many minutes would it take a train to travel

Mathematics
2 answers:
schepotkina [342]3 years ago
6 0
Answer to your question is 45
vladimir1956 [14]3 years ago
3 0

Answer:

45

Step-by-step explanation:

Every 15 minutes, 30 kilometers are passed by.

15/60 = 1/4 hour

30/120 = 1/4 speed

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Whats 3/5 divided by2. I need help on bell work
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\frac{3}{5}÷2=\frac{3}{10}
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What is the smallest positive prime factor of 2017^2019 +2019^2017​
kogti [31]

Answer:

17

Step-by-step explanation:

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Suppose that you want to design a cylinder with the same volume as a given cylinder, but you want to use a different radius and
shutvik [7]

volume of a cylinder = pi×r^2×h

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4 years ago
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Tom was selling his old games. He started out with 57 but sold 37 of them. He put the rest in boxes with 5 games in each. How ma
eduard

Answer:

Tom started out with 57 games but sold 37 of them.

=> Now, Tom has: 57 - 37 =20 games

He put the rest in boxes with 5 games in each.

=> The number of boxes: 20/5 = 4 box

Hope this helps!

:)

8 0
4 years ago
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is
tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

4 0
3 years ago
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