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BabaBlast [244]
3 years ago
5

8≤ 11x-(2x-12) how do you slove this

Mathematics
2 answers:
Natalka [10]3 years ago
6 0
The answer is 1790743356790876432335675434667 hlctiduvobnonigtdsyfib l lnivyftds
AnnZ [28]3 years ago
4 0
First, you distribute the sign, giving you:
8<span>≤11x-2x+12
Then, you simplify, giving you:
8</span><span>≤9x+12
Next, you isolate the variable by subtracting 12 from both sides, resulting in:
-4</span><span>≤9x
Finally, you divide both sides by 9, making the final answer
-4/9</span><span>≤x</span>
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What is the relationship between the conversion factors used in Part A of Model 2? Whatabout the conversion factors used in Part
Lelu [443]

Given:

The conversions from meter to inches and inches to meter are shown in part A of model 2.

The conversions from liters to quarts and quarts to liters are shown in part B of model 2.

Required:

To find the relationship between the conversion factors used in Part A of Model 2.

To find the relationship in the the conversion factors used in Part B of Model 2.

Explanation:

We have given that 1 meter = 39.4 inches.

Thus, from the calculations shown in part A of model 2, we can conclude that the quantity from meters to inches is converted as:

1.5\times39.4=59

Thus, 1.5 m =59 inches.

Also, the quantity from inches to meters is converted as:

\frac{59}{39.4}=1.5

Hence, 59 in = 1.5 m.

Next,

We have 1 L = 1.06 qt.

Thus, from the calculations shown in part B of model 2, we can conclude that the quantity from quarts to liters is converted as:

\frac{186}{1.06}=175

Thus, 186 quarts = 175 L.

Also, the quantity from liters to quarts is converted as:

175\times1.06=186

Hence, 175 L = 186 qt.

Final Answer:

We conclude that:

While converting from meters to inches, we multiply the quantity 1.5 by the equality quantity given.

While converting from incehs to meters, we divide the quantity 59 by the equality quantity given.

Also, While converting from quarts to liters, we divide the quntity 186 by the equality quantity given.

While converting from liters to quarts, we multiply the quntity 175 by the equality quantity given.

6 0
1 year ago
When you find the<br> median of a set of data,<br> what quartile would this<br> number be?
IgorC [24]
I think your question isn’t phrased well
7 0
3 years ago
Write the standard equation of the circle shown.
zysi [14]

Answer:

b

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← r is the radius

The circle shown is centred at the origin and has a radius of 5, thus

x² + y² = 5² ⇒ x² + y² = 25 → b

4 0
3 years ago
Rounding decimals 32.60
UNO [17]
Well, assuming that you need to round to the nearest whole number, what is six closer to? 0, or 10? The answer is 10. Therefore, you would round up to 33. Hope this helps!
7 0
3 years ago
Read 2 more answers
When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis
Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so \mu = 22, \sigma = 4.

What is the probability that a fisherman catches a spotted seatrout within the legal limits?

They must be between 10 and 30 inches.

So, this is the pvalue of the Z score of X = 30 subtracted by the pvalue of the Z score of X = 10

X = 30

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 22}{4}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 22}{4}

Z = -3

Z = -3 has a pvalue of 0.00135.

This means that there is a 0.9772-0.00135 = 0.97585 = 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

3 0
3 years ago
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