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3 years ago

Which container holds more, a Elgin millimeter carton, or a 1 L bottle

Mathematics

1 answer:

anyanavicka [17]3 years ago

7 0

The answer would be a 1 Liter bottle, because a liter is 33 oz rounded and and Elgin millimeter container is 25 oz.

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35% of what number is 35? <br> Please solve all steps using a=p•w

son4ous [18]

35% * X = 35
first you would change 35% to .35
then the equation would be .35 * X = 35
next you would divide .35 from both sides making the equation-
x = 100

then to check plug it in
.35 * 100 = ?
.35 * 100 = 35
want me to message you how to i did it?

4 0

2 years ago

Please help ill give brain

Rasek [7]

Answer:

23 r1

Step-by-step explanation:

23 R 1

28/653

-56

93 bring down three

=1 which is remainder

28*2=56

28*3=92

6 0

3 years ago

Find the value of each expression. 42+6÷2

Scrat [10]

Answer:

Step-by-step explanation:

6/2 = 3

42+3 = 45

3 0

2 years ago

The city of Anvil is currently home to 21000 people, and the population has been growing at a continuous rate of 4% per year. Th

Yanka [14]

Answer:

They'll reach the same population in approximately 113.24 years.

Step-by-step explanation:

Since both population grows at an exponential rate, then their population over the years can be found as:

$\text{population}(t) = \text{population}(0)*(1 + \frac{r}{100})^t$

For the city of Anvil:

$\text{population anvil}(t) = 21000*(1.04)^t$

For the city of Brinker:

$\text{population brinker}(t) = 7000*(1.05)^t$

We need to find the value of "t" that satisfies:

$\text{population brinker}(t) = \text{population anvil}(t)\\21000*(1.04)^t = 7000*(1.05)^t\\ln[21000*(1.04)^t] = ln[7000*(1.05)^t]\\ln(21000) + t*ln(1.04) = ln(7000) + t*ln(1.05)\\9.952 + t*0.039 = 8.8536 + t*0.0487\\t*0.0487 - t*0.039 = 9.952 - 8.8536\\t*0.0097 = 1.0984\\t = \frac{1.0984}{0.0097}\\t = 113.24$

They'll reach the same population in approximately 113.24 years.

4 0

3 years ago

Define four symbolic constants that represent integer 25 in decimal, binary, octal, and hexadecimal formats

stealth61 [152]

Answer:

1) Decimal $25= (25)_{10}$

2) Binary $25= (11001)_2$

3) Octal $25= (31)_8$

4) Hexadecimal $25= (19)_{16}$

Step-by-step explanation:

Given : Integer is 25

To find : Represent integer in decimal, binary, octal, and hexadecimal formats.

Solution :

1) Integer into decimal - To convert into decimal the base goes to 10.

So, $25= (25)_{10}$

2) Integer into binary - To convert into binary the base goes to 2, it form in 0 and 1 and we divide integer by 2.

Divide 25 by 2 and note down the remainders.

2 | 25

2 | 12 R=1 ←

2 | 6 R=0 ↑

2 | 3 R=0 ↑

2 | 1 → R=1 ↑

So, $25= (11001)_2$

3) Integer into octal - To convert into octal the base goes to 8 and we divide integer by 8.

Divide 25 by 8 and note down the remainders.

8 | 25

| 3 → R=1

So, $25= (31)_8$

4) Integer into hexadecimal - To convert into hexadecimal the base goes to 16 and we divide integer by 16.

Divide 25 by 16 and note down the remainders.

16 | 25

| 1 → R=9

So, $25= (19)_{16}$

3 0

3 years ago