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Sergeu [11.5K]
3 years ago
7

When dividing polynomials using factorization, canceling identical factors in the denominator and the numerator will give the __

_____.
Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0

Answer:

Remainder :)

Hope this helps!

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The equation y=5+0.5x represents the cost of getting a car wash and using the vacuum for x minutes. What is the y-intercept?
adell [148]

5 is the y intercept.

-Always the number without the variable.

5 0
3 years ago
Use synthetic division to solve (x^3+1)/(x-1). What is the quotient?
Sav [38]

Answer:

  x^2 +x +1

Step-by-step explanation:

See below for the tableau. The quotient is x^2 +x +1.

___

The remainder is 2.

7 0
3 years ago
The standard deviation of a sample taken from population A is 17.6 for a sample of 25.
lawyer [7]

Answer:

The standard deviation of the sample mean differences is _5.23_

Step-by-step explanation:

We have a sample of a population A and a sample of a population B.

For the sample of population A, the standard deviation \sigma_A is

\sigma_A = 17.6

The sample size n_A is:

n_A = 25.

For the sample of population B, the standard deviation \sigma_B is

\sigma_B = 21.2

The sample size n_B is:

n_B = 30.

Then the standard deviation for the difference of means has the following form:

\sigma=\sqrt{\frac{\sigma_A^2}{n_A}+\frac{\sigma_B^2}{n_B}}

Finally

\sigma=\sqrt{\frac{17.6^2}{25}+\frac{21.2^2}{30}}\\\\\sigma= 5.23

7 0
4 years ago
Select the correct answer from the drop-down menu.
lidiya [134]

Answer:

6y² - 20y + 6

Step-by-step explanation:

Use FOIL method

(3y - 1)(y-3) = 3y*y + 3y*(-3) + (-1)*y + (-1)*(-3)

                 = 3y²- 9y - y + 3    {add the like terms}

                = 3y² - 10y + 3

2(3y - 1)(y - 3) = 2 ( 3y² - 10y + 3)

                      = 2*3y² - 2*10y + 2*3

                      = 6y² - 20y + 6

6 0
3 years ago
PLEASE HELPP
agasfer [191]

Answer:

The solution to the system of equations be:

x=3,\:y=-1

Hece, option B is correct.

Step-by-step explanation:

Given the system of equations

\begin{bmatrix}x-3y=6\\ 2x+2y=4\end{bmatrix}

Multiply x − 3y = 6 by 2:      2x-6y=12

\begin{bmatrix}2x-6y=12\\ 2x+2y=4\end{bmatrix}

so

2x+2y=4

-

\underline{2x-6y=12}

8y=-8

so the system of equations becomes

\begin{bmatrix}2x-6y=12\\ 8y=-8\end{bmatrix}

Solve 8y = -8 for y

8y=-8

Divide both sides by 8

\frac{8y}{8}=\frac{-8}{8}

y=-1

\mathrm{For\:}2x-6y=12\mathrm{\:plug\:in\:}y=-1

2x-6\left(-1\right)=12

2x+6=12

subtract 6 from both sides

2x+6-6=12-6

2x=6

Divide both sides by 2

\frac{2x}{2}=\frac{6}{2}

x=3

Therefore, the solution to the system of equations be:

x=3,\:y=-1

Hence, option B is correct.

6 0
3 years ago
Read 2 more answers
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