Correct question is;
A football is kicked up into the air. Its height, H, above the ground, in meters, at t seconds can be modelled by () = 24 − 4.9²
(a) Determine the expression for the instantaneous rate of change in height at time t.
(b) Determine ' (2) What does ' (2) represent?
Answer:
A) '() = 24 − 9.8
B) '(2) = 4.4 m/s
It means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s
Step-by-step explanation:
We are given the function to represent the height as;
() = 24 − 4.9²
A) expression for the instantaneous rate of change in height at time t will be gotten by differentiation of the height function. Thus;
'() = 24 − 9.8
B) '(2) = 24 - 9.8(2)
'(2) = 4.4 m/s
This means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s
Answer: She attended to 7 weekday games.
Step-by-step explanation:
Let's denote our variables as:
Wd = number of weekday games that she attended.
We = number of weekend games that she attended.
We know that in total, she attended to 23 games, so we have:
Wd + We = 23.
"If Ariel attended nine more weekend games than weekday games" can be written as:
We = Wd + 9.
Then we have the system of equations:
Wd + We = 23.
We = Wd + 9.
The first step would be to replace the second equation into the first one, as:
Wd + We = 23.
Wd + (Wd + 9) = 23
Now we can solve this for Wd.
2*Wd + 9 = 23
2*Wd = 23 - 9 = 14
Wd = 14/2 = 7
She attended to 7 weekday games.
And:
We + 7 = 23
We = 23 - 7 = 16
She attended at 16 weekend games.
since we know the <u>common difference</u> is d is 6, then to get from the 6th term to the 10th term, we use d 4 more times.
6th term..................37
7th term...................37 + 6
8th term...................37 + 6 + 6
9th term...................37 + 6 + 6 + 6
10th term...................37 + 6 + 6 + 6 + 6
.....................................61.
Please see picture above.
Answer:
Step-by-step explanation:
9x - 2c = k
9x = k + 2c
x = (k + 2c)/9
