ANSWER
B. 3 ft by 8 ft
EXPLANATION
The area is given as 24 square feet.
This implies that,
The perimeter of the rectangular field is given as 22 feet.
This implies that,
Or
We make w the subject in this last equation and put it inside the first equation.
When we substitute into the first equation we get;
This implies that,
When l=3, w=24
Therefore the dimension is 3 ft by 8 ft
Answer:Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.
Hope this helped
Since we are already given the formula and all the information, the only thing that we have to do is input all the values and simplify until we get an answer. In addition, we must also note that the radius is 4 (because the diameter is equal to twice the radius, meaning that if the diameter is 8, the radius is 4). Using the formula and information given, we get:
Volume = 3 * (4)² * 12
Which simplifies to:
Volume = 3 * 16 * 12
Volume = 576
Now, we need to know the units. Since this is a 3d shape, and the unit for the lengths of the sides are centimeters, this answer will be in centimeters cubed. That means our answer is 576 centimeters cubed.
The product of 8 and a number, rised to the power of two-thirds
Answer:
D. There were no significant effects.
Step-by-step explanation:
The table below shows the representation of the significance level using the two-way between subjects ANOVA.
Source of Variation SS df MS F P-value
Factor A 10 1 10 0.21 0.660
Factor B 50 2 25 0.52 0.6235
A × B 40 2 20 0.42 0.6783
Error 240 5 48 - -
Total 340 10 - - -
From the table above , the SS(B) is determined as follows:
SS(B) = SS(Total)-SS(Error-(A×B)-A)
= 340-(240-40-10)
= 50
A researcher computes the following 2 x 3 between-subjects ANOVA;
k=2
n=3
N(total) = no of participants observed in each group =11
df for Factor A= (k-1)
=(2-1)
=1
df for Factor B = (n-1)
=(3-1)
=2
df for A × B
= 2 × 1
= 2
df factor for total
=(N-1)
=11-1
=10
MS = SS/df
Thus, from the table, the P-Value for all data is greater than 0.05, therefore we fail to reject H₀.