The probability that exactly 2 voters will be in favor of the ballot initiative is 0.309.
<h2>Given</h2>
Number of voters who support ballot initiative = 30 % = 0.30
Number of voters who does not support this initiative = 1 - 0.30 = 0.70
Number of voters selected for Surveying = 5
<h3>What is probability?</h3>
The probability of success and failure remain the same throughout the trials.
The probability that exactly 2 voters will be in favor of the ballot initiative is given by;
If P denotes Success and Q denotes failure;
Hence, the probability that exactly 2 voters will be in favor of the ballot initiative is 0.309.
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brainly.com/question/20344726
Answer:
its b or c ( im not for sure tho)
Step-by-step explanation:
Answer:
2x + 12y + 43 ≥ 40
17x + 12y + 8z ≥ 20
14x + 6y + z ≤ 50
x ≥ 0
y ≥ 0
z ≥ 0
Step-by-step explanation:
given:
Cost Eggs = $2
Cost of edema = $5
cost of elbow Macaroni = $3
Lets eggs = x,
edamame = y
elbow macaroni = z
TC = 2x+5y+3z
Therefore;
2x + 12y + 43 ≥ 40
17x + 12y + 8z ≥ 20
14x + 6y + z ≤ 50
x ≥ 0
y ≥ 0
z ≥ 0
the first objective is to make sure the total cost is subject to the required nutritional requirements.
So the total cost function (TC) is denoted by the number of servings multiplied for each costs. Eggs cost $2, edamame $5, and macaroni $3.
The problem subjects that each meal contains at least 40g of carbohydrates (this is the condition).
to get this we need to add what each meal component adds to the total, eggs add 2g of carbs, edamame 12g, and macaroni 43g.
Same should be done for protein, we require at least 20 grams of protein, Eggs add 17g, edamame adds 12g, and macaroni adds 8g.
and lastly we don't want more than 50 grams of fat, Eggs add 14g, edamame add 6g and macaroni 1g.
Step-by-step explanation:
The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:
let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9
let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9
let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9
let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9
let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9
let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9
You can continue to increase the length of the square and follow this pattern and it will be consistent.
