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Anarel [89]
3 years ago
7

What is the first 8 multiples of 4?

Mathematics
1 answer:
Ainat [17]3 years ago
8 0
4,8,12,16,20,24,28,32
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GIVING 20 POINTS NEED HELP
alexandr1967 [171]

Answer:

4 is a BCA def of rectangle

6 0
2 years ago
gale's grade in science for the term is determined by the average of five test grades. his first four grades are 80, 95, 78, and
lara [203]

Answer:

He needs at least 77 on the 5th test.

<em>T₅ ≥ 77</em>

Step-by-step explanation:

If five numbers are to average 84, then their sum must be (5 x 84) = 420 .

Gale needs his five grades to add up to 420.

So far, he has (80 + 95 + 78 + 90) =  343 .

He needs at least (420 - 343) = <em>77 more</em> points on the 5th test.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%28m%20%2B%2010%29%20-%202%28m%20-%20n%29%20%20%5C%3A%20what%20%5C%3A%20is%20%5C%3A%20the%20%
Umnica [9.8K]

Answer:

5m+30+2n

Step-by-step explanation:

3m+30 and - 2m+2n

5m+30+2n

8 0
3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
Graph the linear equation and answer each of the following questions. y&gt;2/3 x-2 What is the y-intercept? What is the slope (i
lozanna [386]

Answer:

(i)

y-intercept is -2

(ii)

slope is \frac{2}{3}

(iii)

slope is positive

(iv)

another point is (3,0)

Step-by-step explanation:

We are given equation as

y=\frac{2}{3} x-2

now, we can compare it with slope intercept form of line

y=mx+b

where

m is slope

b is y-intercept

we get

m=\frac{2}{3}

b=-2

So,

(i)

y-intercept is -2

(ii)

slope is \frac{2}{3}

(iii)

we can see that

m=\frac{2}{3}

is a fraction and positive

so, slope is positive

(iv)

we can select any random value of x and find y

that will give us second point

Let's assume

x=3

y=\frac{2}{3}\times 3-2

y=2-2

y=0

So, another point is (3,0)

(v)

Graph:


4 0
3 years ago
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