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asambeis [7]
3 years ago
8

Solve for x 6x^2-5+-21=0

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0

Answer:

Step-by-step explanation:

I believe your 6x^2-5+-21=0 should be 6x^2 - 5x - 21=0.

Let's use the quadratic formula to solve for x.

Here the coefficients are a = 6, b = -5 and c = -21.  

The discriminant is b^2-4ac, which here is (-5)^2 - 4(6)(-21), or 529.

The square root of 529 is 23.

Thus, the roots (solutions) are:

       -(-5) ± 23            28

x = ----------------- = ------ = 7/3     and     also    x = -3/2

           2(6)              12

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Step 1; We must find the point in the graph where the lines of y=2.5x+2 and y=2x+4 intersect. To find out the intersecting point we must substitute values of x in both equations and see in which co-ordinate they are the same.

Step 2; We plot various values of x on the line governed by the equation y=2.5x+2

For a value of x=1 , y=2.5(1) + 2 = 4.5

For a value of x=2 , y=2.5(2) + 2 = 7

For a value of x= 3, y=2.5(3) + 2 = 9.5

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