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REY [17]
3 years ago
9

Solve the system of equations: 6x - 5y = 15 x = y + 3

Mathematics
1 answer:
Anettt [7]3 years ago
4 0

Answer:

x = 0, y = -3

Step-by-step explanation:

plug in x as y + 3 into the first equation

6(y+3) - 5y = 15

6y+18 - 5y = 15

y = -3

x= 0

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Write a decimal that is 1 tenth of 0.9
tigry1 [53]
1/10 = 0.1

0.9 x 0.1 = 0.09

0.09 is your answer

hope this helps
4 0
3 years ago
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zmey [24]

Answer:

16

Step-by-step explanation:

4 0
3 years ago
I will give u brainliest
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3 years ago
Read 2 more answers
I have some cheese. I used
hram777 [196]
<h3>Answer:     2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

3C = 4500

C = 4500/3 .... divide both sides by 3

C = 1500

This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

3A = 7500

A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

6 0
3 years ago
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