Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
Answer:
the answer is D. 147 degrees
Step-by-step explanation:
114+33=147
check answer by
180-147=33
33+33+114=180
Answer:
V=1890mm
Step-by-step explanation:
You must use its formula: which is
V=(Length x height x width) / 3
V=(15x18x21)/3
V=5670/3
V=1890mm
Answer:
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Step-by-step explanation:
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Answer:
y - 7 = (x + 5)
Step-by-step explanation:
Point-slope form: y - y1 = m(x - x1)
Slope(m) = 1
Point: (-5, 7) = (x1, y1)
To write the equation in point-slope form, we need to know the slope and one point. Since we were already given the values of the slope and one point, all we have to do is input those values into the equation:
y - y1 = m(x - x1)
y - 7 = 1(x - (-5))
y - 7 = (x + 5)
The equation in point-slope form is: y - 7 = (x + 5)
