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mart [117]
3 years ago
15

Find side A of a triangle with a B length of 7 and a C length of 25

Mathematics
2 answers:
Ksju [112]3 years ago
5 0

Answer:

A

Step-by-step explanation:

C - B < A < C + B

25 - 7 < A < 25 + 7

18 < A < 32

A can have any length between 10 and 32.

In case it's a right angle triangle,

A² = 25² - 7²

A² = 576

A = 24

Vikentia [17]3 years ago
4 0

Answer:

A 24

Step-by-step explanation:

Assuming this is a right triangle, we can use the Pythagorean theorem

a^2+ b^2 = c^2

a^2 + 7^2 = 25^2

a^2 +49= 625

Subtract 49 from each side

a^2 +49-49 = 625-29

a^2 = 576

Take the square root of each side

sqrt(a^2) = sqrt(576)

a = 24

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eduard
In this problem, you're looking for the value of t, so that f(t) = 48. That means if you put t into 5t-7, you'll get 48. To do this set up and solve an equation for t by setting 48 equal to 5t-7:
5t-7=48

Isolate the variable by adding 7 to both sides. 
5t=55

Divide by 5 on both sides to find t.
t=11

The answer is 11.


8 0
3 years ago
Solve for m. <br> 2(5m + 4) = 2 (3m - 10)
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2(5m+4)=2(3m-10)
10m+8= 6m-20
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3 0
3 years ago
Simplify − 2/3 − 3/5 .
zzz [600]
-19/15 

you multiply boh sides by the other denomonater

-10           and -9
15                   15
4 0
3 years ago
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Choose the equation that is equivalent to: 4(8x+6)=20
KengaRu [80]

Answer:

B

Step-by-step explanation:

32x + 24 = 20

24 - 24= 0

20 - 24=  -4

32x = -4

32x/32

x

-4/32= -8

X= -1/8

7 0
2 years ago
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If cos(x) = Three-fourths and tan(x) &lt; 0, what is cos(2x)?
makvit [3.9K]

Step-by-step explanation:

The value of sin(2x) is \sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

How to determine the value of sin(2x)

The cosine ratio is given as:

\cos(x) = -\frac 14cos(x)=−

4

1

Calculate sine(x) using the following identity equation

\sin^2(x) + \cos^2(x) = 1sin

2

(x)+cos

2

(x)=1

So we have:

\sin^2(x) + (1/4)^2 = 1sin

2

(x)+(1/4)

2

=1

\sin^2(x) + 1/16= 1sin

2

(x)+1/16=1

Subtract 1/16 from both sides

\sin^2(x) = 15/16sin

2

(x)=15/16

Take the square root of both sides

\sin(x) = \pm \sqrt{15/16

Given that

tan(x) < 0

It means that:

sin(x) < 0

So, we have:

\sin(x) = -\sqrt{15/16

Simplify

\sin(x) = \sqrt{15}/4sin(x)=

15

/4

sin(2x) is then calculated as:

\sin(2x) = 2\sin(x)\cos(x)sin(2x)=2sin(x)cos(x)

So, we have:

\sin(2x) = -2 * \frac{\sqrt{15}}{4} * \frac 14sin(2x)=−2∗

4

15

∗

4

1

This gives

\sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

6 0
2 years ago
Read 2 more answers
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