3 years ago

Find the distance between (1,0) and (9, 15). Distance =

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

6 0

Answer:

d = 17

Step-by-step explanation:

d = √ (9 − 1) 2 + (15− 0)^2

d = √ (8) ^2 + (15) ^2

d = √ 64 + 225

d = √289

d = 17

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Haruka hiked several kilometers in the morning. She hiked only 6 kilometers in the afternoon, which was 25%, percent less than s

Semenov [28]

Answer:

14 km

Step-by-step explanation:

6 km in the afternoon

x km in the morning

6= x- 25%

6= 0.75x

x= 6/0.75

x= 8 km

total 6+8= 14 km

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4 years ago

Solve for x in the triangle. Round your answer to the nearest tenth.

hodyreva [135]

Answer:

x ≈ 11.7

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos26° = $\frac{adjacent}{hypotenuse}$ = $\frac{x}{13}$ ( multiply both sides by 13 )

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3 years ago

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Luden [163]

The sum is of n and 14 can be written as:

n+14=72

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3 years ago

Consider The following pair of equations the two equations are graft at what point do the lines representing the two equations i

ANEK [815]

Answer:

Step-by-step explanation:

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3 years ago

What are the amplitude, period, and phase shift of the given function? f(t)=-2/3 cos (3t-3pi)

dybincka [34]

Answer:

amplitude; $\frac{2}{3}$

Phase shift; $\pi$ units right

Period; $\frac{2\pi}{3}$

Step-by-step explanation:

The given function is

$y=-\frac{2}{3}\cos(3t-3\pi)$

This function is of the form;

$y=A\sin (Bt+C)$

The period is given by:

$|A|=|-\frac{2}{3}|= \frac{2}{3}$

The period is given by:

$T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}$

The phase shift is given by;

$\frac{C}{B}=\frac{-\3pi}{3}=- \pi$ or $\pi$ units right.

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3 years ago