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s2008m [1.1K]
2 years ago
15

What term is used to describe the study of using limited resources to fulfill wants and needs?

Mathematics
2 answers:
amid [387]2 years ago
6 0

Answer: C, management

stealth61 [152]2 years ago
5 0
It’s b economics because I’ve already came across the exact question and everyone in the comments had answered B and were saying that their teachers said it was b as well as tutors.

It’s economics
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5. A basketball player averages 10.2 points per
zvonat [6]

Answer:  11.15

Step-by-step explanation:

10.2 + 12.1 = 22.3 is the total amount of points averaged each game together

22.3 divided by 2 + 11.15

11.15 is the average of the two players over the 10 games

4 0
3 years ago
A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ 
E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ 
P(E^{c})= \frac{3}{12} \\  \\ 
P(E^{c})= \frac{1}{4}
7 0
3 years ago
A woman bought some large frames for $10 each and some small frames for $5 each add a closeout sale if she bought 20 frames for
vampirchik [111]

Answer:

The quantity of large frames is 7

The quantity of small frames is 13

Step-by-step explanation:

Given as :

The price of each large frames = $ 10

The price of each small frames = $ 5

The total number of both frames bought = 20

The price for both the frames = $ 135

Now,

Let the quantity of large frames = L

And The quantity of small frames = S

So , According to question

The total number of both frames bought = 20

Or, The quantity of large frames + the quantity of small frame = 135

Or, L + S = 20         ......A

And $ 10 L + $ 5 S = $ 135                         ................B

Or, $ 10× ( L + S ) = $ 10× 20

Or, $ 10 L + $ 10 S = $ 200

(  $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135

Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65

Or, 0 + 5 S = 65

∴  S = \frac{65}{5}

I.e S = 13

So, The quantity of small frames = S = 13

Put the Value of S in eq A

So , L + S = 20

Or, L = 20 - S

Or, L = 20 - 13

∴   L = 7

So, The quantity of large frames = L = 7

Hence The quantity of large frames is 7

And   The quantity of small frames is 13   Answer

7 0
3 years ago
If the simple interest on ​$4000 for 3 years is ​$720​, then what is the interest​ rate?
solong [7]

Answer:

0.06% annually

Step-by-step explanation:

Divide $720 by 3. We get $240, so we know this is the amount of interest we get per year. Dividing $240 by $4,000 gives us

\frac{240}{4000} = 0.06

4 0
2 years ago
22-28d = - 12 ??? geometry is hard
yarga [219]
There's not much you can or should do here other than to "solve for d."

Subtract 22 from both sides.  Then 22 - 22 - 28d = -12 - 22 = -34

Then -28d = -34, and d = -28 / (-34) = + 14/17 (answer)
3 0
3 years ago
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