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Zolol [24]
2 years ago
7

A football conference is making a histogram of number of points scored in each game by its 14 team for the 12 weeks each team pl

ayed (168 scores). The scores range from 0 to 70. What scale should be used for the x-axis?
These are the answer choices:
A) 1 point
B) 5 points
C) 15 points
D) 20 points
YOUR answer must be specific, and I will mark brainliest + a thanks. 11 pointer
Mathematics
2 answers:
Assoli18 [71]2 years ago
5 0
This is more of a common sense problem rather than actual math.
Since we are trying to see the distribution of scores, it is not very practical to use 1 point. 15 and 20 point distributions are a bit big. Thus, the answer is 5 (most histograms in math class do use 5 for their scale).
ryzh [129]2 years ago
3 0

Answer:

its 5 points

Step-by-step explanation:

i did it on usatestprep

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Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

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Step-by-step explanation:

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