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nalin [4]
3 years ago
10

If a pool table measures 4 ft by 8 ft , what is the diagonal length from the bottom right pocket to the nearest tenth?

Mathematics
1 answer:
puteri [66]3 years ago
5 0

Answer:

8.9 ft

Step-by-step explanation:

Use Pythagorean theorem,

a² + b² = c²

√(a² + b²) = c

The diagonal is the hypotenuse of the rectangular pool table.

So,

√(4² + 8²) = c

√(16 + 64) = c

√(80) = c

8.944... = c

Nearest tenth:

8.9

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Wesley and Mia deposit $800.00 into a savings account which earns 15% interest compounded annually. They want to use the money i
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Step-by-step explanation:

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4 0
4 years ago
Line segment GT contains the point G(−3, 5) and a midpoint at A(1, −4). What is the location of endpoint T?
algol [13]

Imagine you're moving along the segment. Since the midpoint is in the middle of the segment (obviously), it means that when you've traveled from G to A, you're halfway through your journey, along both x and y directions. So, let's break the problem in two and analyze both directions.


Along the x axis, you've moved from -3 to 1, so you moved 4 units forward. This means that you have 4 units still to go, and your journey will end at coordinate 5.


Similarly, along the y axis, you've moved from 5 to -4, so you moved 9 units downward. This means that you have 9 units still to go, and your journey will end at coordinate -13.


So, the coordinates of the endpoint are T = (5,-13)


If you prefer a more analyitical approach, simply write the definition of the midpoint and solve it for the coordinates of T.


We have G = (-3, 5) and T = (x_T,y_T). The midpoint is computed as


A = \left( \frac{-3+x_T}{2},\frac{5+y_T}{2} \right) = (1, -4)


So, you have the equations


\frac{-3+x_T}{2} = 1,\qquad \frac{5+y_T}{2} = -4


Multply both equations by 2 to get


-3+x_T = 2,\qquad 5+y_T = -8


Move the constants to the right hand sides to get


x_T = 5,\qquad y_T = -13

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3 years ago
If ABC ~ DEF what is the scale factor of abc to def
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3 years ago
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