13, because 78 postcards divided by 6 cards per board = 13 poster boards
Answer:
b) 0.0625
Step-by-step explanation:
Answer: See the pictures
Step-by-step explanation:
Hope I helped!
Sorry it took so long btw
Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
● Answer:
8.995 cm
● Step-by-step explanation:
P = d + L/2
d = 3.5 cm
L/2 = 2pi×r/2
= pi×d/2
= 3.14×3.5/2
= 5.495 cm
P = 3.5cm + 5.495
= 8.995 cm
