Answer:
4/5 divided by 9/10
4/5 times 10/9
=8/9
Step-by-step explanation:
hope this help you good luck
Answer: The required percentage would be 5.4%.
Step-by-step explanation:
Since we have given that
Worth of Company A = $4150
Worth of Company B = $6820
So, increase in Company A = 6%
increase in Company B = 5%
According to question, it becomes,

So, the total percentage increase in the investor's stock account would be

Hence, the required percentage would be 5.4%.
+ <span>use t for the number of hours the meeting room is rented
+ </span><span>college charges a reservation fee of $49 and an additional fee of $5.40 per hour.So we have 49+ 5.40t
+ </span>the film club wants to spend less than $81.40 on renting the meeting room, and we need:<span>49+ 5.40t< 81.40
or 5.40t < 81.40- 49
and 5.40t< 32.40
t< 32.40: 5.40= 5.629
So </span><span>the possible amounts of time for which they could rent the meeting room 5.6 hours</span>
Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
You would have spent $6.50. All you need to do is multiply the weight by the price. 1.25 * 5.20