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prohojiy [21]
3 years ago
15

Jennifer spent $100 at the mall, during tax free weekend.

Mathematics
1 answer:
zhenek [66]3 years ago
8 0

Answer:

A.75%

Step-by-step explanation:

55+20=75 and the other percentage is 25

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Multipy the expreshions (2h+2.7) (2h-27)​
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Answer:

4h^2-48.6h-72.9

Step-by-step explanation:

(2h+2.7) (2h-27)\\4h^2-54h+5.4h-72.9\\4h^2-48.6h-72.9

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If you help me i give 100 pts
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ANSWER:

450

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Step-by-step explanation:

5 0
2 years ago
If a constant of proportionality is 1/5, what would the new constant of proportionality be if the x and y axes were flipped? (an
mixas84 [53]

Answer:

5/1 or 5

Step-by-step explanation:

don't take my word for it but if i understand correctly all you have to do is flip the 1 and 5 which is called the recipicoal  

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Clarge%7B%5Cbold%20%5Cred%7B%20%5Csum%20%5Climits_%7B8%7D%5E%7B4%7D%20%7Bx%7D%5E%7B2%7D%2
kiruha [24]

Answer:

No solution

Step-by-step explanation:

We have

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

For the sum it is not correct to assume

$\sum_{x=8}^{4}x^2= 8^2 + 7^2+6^2+5^2+4^2 = 64+49+36+25+16 = 190$

Note that for

$\sum_{x=a}^b f(x)$

it is assumed a\leq x \leq b and in your case \nexists x\in\mathbb{Z}: a\leq x\leq b for a>b

In fact, considering a set S we have

$\sum_{x=a}^b (S \cup \varnothing) = \sum_{x=a}^b S + \sum_{x=a}^b \varnothing $ that satisfy S = S \cup \varnothing

This means that, by definition \sum_{x=a}^b \varnothing = 0

Therefore,

$\sum_{x=8}^{4}x^2 = 0$

because the sum is empty.

For

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

we have other problems. Actually, this case is really bad.

Note that \cos^2(\infty) has no value. In fact, if we consider for the case

$\lim_{x \to \infty} \cos^2(x)$, the cosine function oscillates between [-1, 1] , and therefore it is undefined. Thus, we cannot evaluate

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

and then

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

has no solution

7 0
2 years ago
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