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zmey [24]
3 years ago
12

A recent report shows that 62% of people are interested in black holes. If this number is down from the previous year by 8%, wha

t was the percent of
Mathematics
1 answer:
marishachu [46]3 years ago
6 0

Answer:

54

Step-by-step explanation:

62-8=54

the percent decrease so you subtract

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Of the 300 fifth graders at Benson Elementary School, 40% signed up for an after-school activity. How many students signed up fo
Trava [24]

Answer: 120 students

Step-by-step explanation:

multiply 40 by 300 then divide by 100 = 120

4 0
2 years ago
Given <br><img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20
Naily [24]

Answer:

\displaystyle y = x^{-\frac{2}{3}}

Step-by-step explanation:

<u>Logarithms</u>

Some properties of logarithms will be useful to solve this problem:

1. \log(pq)=\log p+\log q

2. \displaystyle \log_pq=\frac{1}{\log_qp}

3. \displaystyle \log p^q=q\log p

We are given the equation:

\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }

Applying the second property:

\displaystyle  \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}

Substituting:

\displaystyle \log_{2}(x) = 3\log_{2}(xy)

Applying the first property:

\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))

Operating:

\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)

Rearranging:

\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)

Simplifying:

\displaystyle -2\log_{2}(x) =3\log_{2}(y)

Dividing by 3:

\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}

Applying the third property:

\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)

Applying inverse logs:

\boxed{y = x^{-\frac{2}{3}}}

7 0
3 years ago
The table shows a proportional relationship between the number of meals
Kisachek [45]
B is the answer there is a common denominator y’a welcome
4 0
3 years ago
How do you solve this equation: -2m+3=|15+m|
Elden [556K]

Any number inside the modulus sign becomes positive. This means |15+m|=|-(15+m)|=|-15-m| and so we have,

-2m+3=|15+m| \Rightarrow \left \Big\{ {{-2m+3=15+m} \atop{-2m+3=-15-m}} \right

Solving these gives us

-2m+3=15+m \Rightarrow m=-4

-2m+3=-15-m \Rightarrow = m=18

However if we check the second solution in the original equation we obtain -2(18)+3=|15+18| \Rightarrow -33=33. This is false and so m=18 can't be a solution.

Therefore the only solution is m=-4.

(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)

8 0
3 years ago
Aiden bought 15 chicken wings for $10. What was the cost of the wings in wings per dollar?
Verdich [7]

Answer: $1.50

Step-by-step explanation:

15/10=1.5

6 0
2 years ago
Read 2 more answers
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