A square has two pairs of parrallel lines :) I hope it helps :)
Sorry but i only know the answer for the 1st question.
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If the angles are complementary they measure 90°.
1st find half of 90
which is 45.
Find 4 more than 45.
which is 49°
then subtract 90-49=41
so the measurement of the 2 angles are
49 and 41
Hope it helps!!
To solve these problems, you usually have a favor the numerator. For example, on #7, label your terms, 1 from m^2 is A, -6m from -6 is B and your constant, 8, is C. Next you have to find out what two numbers can be multiplied to give you for C term but can also add together to give you your B term. For this specific problem, -4 and -2 gives you 8 and also adds to be -6. After that, you put your -4 and -2 into their own separate parentheses along with the M from M^2. It should look this like: (m-4)(m-2)/(m-2). Now you notice that the binomial on the bottom and one of the binomials on top is the exact same, so you would cancel that out and your answer would be (m-4).
I'm assuming a quarter-circle is exactly 1/4 of a circle. Thus if you have 4 congruent quarter-circles, that should mean they make a complete circle.
If that is the case, then we can find the area of the full circle using pi*r^2.
So the area of the circle is 5^2*pi or 25pi.
To find the area of the shaded region, we subtract the area of the circle from the area of the square.
The area of the square is 10^2 or 100.
So the area of the shaded region is 100 - 25pi.
My calculator says that equals roughly 21.46
