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yaroslaw [1]
3 years ago
6

Find the area of the irregular figure . ( Assume that all angles are right angles )

Mathematics
2 answers:
masha68 [24]3 years ago
7 0
If you multiplied 2x3 you get the area of half of the whole figure. But to get the other portion I subtracted 4-3 and got 1, the I multiplied 5x1 and got 5. so the answer is 11in^2.
Troyanec [42]3 years ago
7 0

Answer:

Step-by-step explanation:

From the given figure, divide the proportion in such a way that we have two rectangles, then Area of one rectangle=l{\times}b=2{\times}3=6 sq inches

and area of the another triangle=l{\times}b=5{\times}1=5 sq units

Therefore, Area of the irregular figure= Area of rectangle 1 + arae of rectangle 2

=6+5=11 sq inches

Thus, area of the irregular figure= 11 sq inches.

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An example of a trig function that includes multiple transformations and how it is different from the standard trig function is; As detailed below

<h3>How to interpret trigonometric functions in transformations?</h3>

An example of a trigonometric function that includes multiple transformations is; f(x) = 3tan(x - 4) + 3

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Another way to look at it is by;

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We can verify this with the graph

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