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2 years ago

6

Find the area of the irregular figure . ( Assume that all angles are right angles )

2 answers:

masha68 [24]2 years ago

7 0

If you multiplied 2x3 you get the area of half of the whole figure. But to get the other portion I subtracted 4-3 and got 1, the I multiplied 5x1 and got 5. so the answer is 11in^2.

Troyanec [42]2 years ago

7 0

Answer:

Step-by-step explanation:

From the given figure, divide the proportion in such a way that we have two rectangles, then Area of one rectangle= $l{\times}b=2{\times}3=6 sq inches$

and area of the another triangle= $l{\times}b=5{\times}1=5 sq units$

Therefore, Area of the irregular figure= Area of rectangle 1 + arae of rectangle 2

= $6+5=11 sq inches$

Thus, area of the irregular figure= 11 sq inches.

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A trapezoid has the dimensions shown below. Which of these measurements are between 6 and 9?

JulijaS [17]

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3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

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2 years ago

Genevieve works on her scrapbook from 11:27 am to 11:58 am. How many minutes does she work on her scrapbook

Mnenie [13.5K]

Answer:

31

Step-by-step explanation:

time is tricky due to the 60 minute interface. In those questions add to the lower number until you hit a rounded number.

Fortunately you don't need to use this in this problem, and can just subtract 58-27 to get 31

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2 years ago

Which function has a horizontal asymptotes of y=3?

VLD [36.1K]

Answer:

2

Step-by-step explanation:

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2 years ago

Read 2 more answers

Brandon and his children went into a bakery and where they sell donuts for $1.25 each and cookies for $0.25 each brandon has $5.

zvonat [6]

Answer

4 doughnuts

Step-by-step explanation:

.25 times 2 is .5

5.5-.5=5

5/1.25=4

5 0

2 years ago