What is the solution to this system of equation y=4/3x-1

Mathematics

2 answers:

nikdorinn [45]3 years ago

4 0

\left[y \right] = \left[ -1+\frac{4\,x}{3}\right][y]=[−1+34x] totally answer

Vinvika [58]3 years ago

4 0

Plot the points

( 0 , 1 ) and ( 3 , − 3 ) and connect them with a straight line

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Please help me with this!

Igoryamba

Answer:

1: 39,284

2: 58,672.8

3: 2,066.79153912

4: 183.801664976

5: 8,744,119.16410

Those are the answers to the problems now you can just determine which ones are from least to greatest

7 0

4 years ago

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Olegator [25]

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What is the fourth term in the binomial expansion (a+b)^6)

Dafna11 [192]

Answer:

$20a^3b^3$

Step-by-step explanation:

<u>Binomial Series</u>

$(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n$

<u>Factorial</u> is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example: 4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

$\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3$

$\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3$

$\implies \dfrac{6!}{3!3!}a^{3}b^3$

$\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3$