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yarga [219]
3 years ago
6

20 POINT PLEASE QUICKLY

Mathematics
1 answer:
sdas [7]3 years ago
5 0

Answer: the ordered pair is (-14,-6)

Step by step:

x – 2y = -2    (Eq. 1)

x – 4y = 10   (Eq. 2)

Isolate x in Eq. 2:

x = -2 + 2y

Substitute that solution x in Eq. 2:

x - 4y = 10

-2 + 2y - 4y = 10

Solve for y:

-2 - 2y = 10

-2y = 10 + 2 = 12

y = -6

Then calculate value for x using the above value for y

x = -2 + 2y

x = -2 + 2(-6) = -14

The solution is (x,y)=(-14,-6)    

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Since out test is right tailed.

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$t_0=\frac{(9.4-6.5)}{\sqrt{\frac{6.25}{12}+\frac{5.76}{12}}}$

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\text{Critical value}

The value of $|t_{1/2}|$ with minimum $\left(n_1-1,n_2-1)$ that is 11 df is 1.363

We go $|t_0|=2.899$ and $|t_{1/2}|$ = 1.363

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Since the value of |t_0|>|t_{1/2}|$  and we reject the H_0

The p-value : right tail H_a:(p>2.8988)

                                      = 0.00724

Therefore the value of $p_{0.1} > 0.00724$, and so we reject the H_0

Thus we are testing 'the difference of means" in this problem.

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