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3 years ago

Help Plzzzzzzzzzzzzzzzzzzz

Mathematics

1 answer:

svetlana [45]3 years ago

6 0

Answer:

Step-by-step explanation:

"binomial" the operation between two terms (B or C)

"3rd degree binomial" the highest degree of the polynomial's monomials (individual terms) with non-zero coefficients have to be "3"

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Prove that (4n+1)^2(4n-1)^2 is a multiple of 8 for all integers of n.<br><br> thanks.

azamat

Answer: i think (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:

(4n + 1)²(4n - 1)²

= [(4n + 1)(4n - 1)]²

= (16n² - 1)²

= 16².n².n² - 2.16.n² + 1

= 8n²(32n² - 4) + 1

can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8

=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.

Step-by-step explanation:

6 0

3 years ago

For your friend's birthday, you have 3 presents to wrap. Find the combined surface area of these 3 gifts so you know how much wr

omeli [17]

The answer is: 5,614 square inches.

The explanation is shown below:

1. The gift on the bottom is a rectangular prism. To calculate its surface area, you must apply the following formula:

$SA=2[(l)(w)+(l)(h)+(h)(w)]$

Where $l$ is the length (20 inches), $w$ is the width (42 inches) and $h$ is the heigth (16 inches).

2. Substitute values:

$SA1=2[(20in)(42in)+(20in)(16in)+(16in)(42in)]=3,664in^{2$

3. The surface area of the other gifts can be calculated with the formula for calculate the surface area of a cube:

$SA=6s^{2}$

Where $s$ is the side.

4. The surface area of the bigger cube is:

$SA2=6(15in^{2})=1,350in^{2}$

5. The surface area of the smaller cube is:

$SA3=6(10in^{2})=600in^{2}$

6. The total surface area (the combined surface area of the three gifts) is:

$SAt=SA1+SA2+SA3\\SAt=3,664in^{2}+1,350in^{2}+600in^{2}\\SAt=5,614in^{2}$

7 0

3 years ago

PLS HELP I'LL MARK BRAINLEST I GIVE 100 POINTS D:

bonufazy [111]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is 7 1 / 5 - 6 2/5

Lunna [17]

$7\dfrac{1}{5}=\dfrac{7\cdot5+1}{5}=\dfrac{35+1}{5}=\dfrac{36}{5}\\\\6\dfrac{2}{5}=\dfrac{6\cdot5+2}{5}=\dfrac{30+2}{5}=\dfrac{32}{5}\\\\7\dfrac{1}{5}-6\dfrac{2}{5}=\dfrac{36}{5}-\dfrac{32}{5}=\dfrac{36-32}{5}=\boxed{\dfrac{4}{5}}$

$7\dfrac{1}{5}-6\dfrac{2}{5}=(7-6)+\left(\dfrac{1}{5}-\dfrac{2}{5}\right)=1+\dfrac{1-2}{5}=1+\dfrac{-1}{5}=1-\dfrac{1}{5}\\\\=\dfrac{5}{5}-\dfrac{1}{5}=\dfrac{5-1}{5}=\boxed{\frac{4}{5}}$

4 0

3 years ago

Find all intercepts of y=x^2-2x-3

morpeh [17]

There is a math graping app called desmos it can help you graph the equation and give you the intercepts

3 0

3 years ago