It always helps to draw a picture. Given the information, Segment OF is the center line that is bisecting this angle.
Since it's bisecting (cutting in half)... we can simply set the two angles equal to each other.
y+30=3y-50
-2y+30=-50
-2y=-80
y = 40
C)40.
Answer:
x over y using the numbers given
Step-by-step explanation:
Answer:
Some of the Exponents = -2 that is true, not 2.
Step-by-step explanation:
Let's check one at a time.
(a)The 6 without an exponent is equivalent to the 6 having a 0 exponent.
and 
= 6 (no exponent. 6 
1 therefore this statement is False.
(b)The sum of the exponents is -2.
let's check , if the base is same we can add the exponents that is the exponent rule.(well established).
if we add exponents in the given expression we get.
, therefore we can see that the sum of the exponents = -2 this is true.
(c) An equivalent expression is 65.6-7, lets evaluate our above expression, it is equal to 
which we can see that 
,therefore this statement is false as well.
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
