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3 years ago

Find the area of the region between the curves y=12-x^2 and y=x^2-6

Mathematics

1 answer:

marissa [1.9K]3 years ago

8 0

Here is my solution

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Geomtry plz help 15 points

VladimirAG [237]

Answer:

m∠E=57°

Step-by-step explanation:

∠FDE=∠FED=(4x+1)° (base angles of isos triangle)

2(4x+1)+(5x-4)=180 (angle sum of triangle)

8x+2+5x-4=180

13x-2=180

13x=180+2

=182

x=182÷13

=14

Hence, m∠E = (4x+1)°

= [4(14)+1]°

= (56+1)°

= 57°

5 0

2 years ago

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Please help with this question

vredina [299]

165 - 57 and divide that by 2. So that would be 54

5 0

3 years ago

ASAP someone please simply two exponents

zhannawk [14.2K]

Answer:

1.) $m^{15}$

2.) $=\frac{1}{y^{15}}$

Give me a comment if you want the explanation.

1.) $\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\left(m^3\right)^5=m^{3\cdot \:5}$

$\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15$

$=m^{15}$

2.) $\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\left(y^{-3}\right)^5=y^{-3\cdot \:5}$

$=y^{-3\cdot \:5}$

$=y^{-15}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\frac{1}{y^{15}}$

4 0

3 years ago

Charles is camping. His campsite is 7/8 miles away. He walks at a speed of 1 7/8 miles per hour. How many minutes will it take h

eduard

Answer

28 minutes or 7/15 of an hour

Step-by-step explanation:

We know that Rate*Time = Distance. Because we are given distance and rate, we can easily change the equation to Distance/Rate = Time.

7/8 / 1 7/8 =

7/8 / 15/8 =

7/8 * 8/15 =

7/15 hour

7/15 * 60 = 28 minutes

3 0

3 years ago

Solve the following problems for x.

yKpoI14uk [10]

3 (4x-7)+x

Solve!

here- first distribute then combine like terms then you will find your solution.

5 0

3 years ago

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