I will say 36 but I also will say wait on someone else to answer
Answer:
In this case, the mass of the car and the force exerted on it are provided as information. Therefore, the acceleration of the car is 0.5 m s−2 when its engine exerts a force of 600 N
Step-by-step explanation:
Answer with Step-by-step explanation:
Since we have given that
Initial velocity = 50 ft/sec =
Initial height of ball = 5 feet =
a. What type of function models the height (ℎ, in feet) of the ball after tt seconds?
As we know the function for height h with respect to time 't'.
b. Explain what is happening to the height of the ball as it travels over a period of time (in tt seconds).
What function models the height, ℎ (in feet), of the ball over a period of time (in tt seconds)?
if it travels over a period of time then time becomes continuous interval . so it will use integration over a period of time
Our function becomes,
m = (360 - 355)/(49 - 40) = 5/9
y = m(x - h) + k
V = 5/9(T - 40) + 355
V = 5/9T - 200/9 + 3195/9
V = 5/9T + 2995/9
V = 0.555T + 332.8
For T = 60
V = 555*60 + 332.8 = 366 m/s
Four loan balances are $6,500, $3,600, $5,400, and $7,500, respectively. The current interest rates for the loans are 7%, 5%, 6%
My name is Ann [436]
[(455 + 180 + 324 + 675)/(65 + 36 + 54 + 75)] = 7.10
Answer is D.