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Over [174]
3 years ago
7

shira was riding the screamer when it broke down. her seat was 53 jorizontal feet from the central support pole. What was her se

at's angle of rtation. Is there more tahn one possible solutions
Mathematics
1 answer:
ki77a [65]3 years ago
5 0

Answer:

The possible solutions are 58 degree, 122 degrees, 302 degrees and 238 degrees

Step-by-step explanation:

Please see the attachment

From the figure, it is evident that

cos AOB = OB/OA = 53/100 = 0.53

Thus, cos-1 (0.53) = 58 degrees

AOB = 58 degree

Also, there are can be other values depending on the quadrants

COB = 180 -58 = 122 degrees

FOB = 360 -58 = 302 degrees

EOB = 180 + 58 = 238 degrees

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a missile is launched from the ground. its height, h(x), can be represented by a quadratic function in terms of time, x, in seco
fomenos

Answer:

The height of the missile in the air  after 11 seconds is 330 feet.

Step-by-step explanation:

The standard form for the quadratic function f(x)= ax^2 + bx + c, which is the function of the parabola model.

We are given two points.

(1, 130) and (2, 240)

Here the first coordinate represents the x (time) and the second coordinate represents h(x), which is height.

Now plug these two coordinates and find the two equations.

(1, 130), the equation is

130 = a.(1)^2 + b(1) + c, where "c" is the initial height. Which is equal to zero.

Therefore, we get

130 = a + b + 0

a + b = 130 -------(1)

Now let's form the second equation using the coordinate (2, 240)

240 = a(2)^2 + b(2) + 0

240 = 4a + 2b -------------(2)

Now let's solve the equations (1) and (2) and find the value of "a" and "b"

a + b = 130 can be written as a = 130 - b

Here we can use the substitution method.

Now plug in a = 130 - b in the second equation, we get

240 = 4(130 - b) + 2b

240 = 520 - 4b + 2b

240 = 520 - 2b

2b = 520 - 240

2b = 280

Dividing both sides by 2, we get

b = 140

Now plug in b = 140 in a = 130 -b and find the value of a

a = 130 - 140

a = -10

Now we got a = -10 and b = 140.

We plug in a = -10 and b = 140 in the general form, we gety

h(x) = -10x^2 + 140x + c

Where c is the initial height, which is equal to 0.

h(x) = -10x^2 + 140x

Now plug in x = 11 seconds and find the height.

h(11) = -10(11)^2 + 140 (11)

= -10 (121) + 1540

= - 1210 + 1540

h(11) = 330 feet,

Therefore, the height of the missile in the air  after 11 seconds is 330 feet.

6 0
3 years ago
Solve for x. <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20%20%3D%20%20-%207" id="TexFormula1" title=" \frac{
weeeeeb [17]

Answer:

x = -14

Step-by-step explanation:

\frac{x}{2} = -7

multiply 2 on both sides

the 2's cancel out on the fraction side, leaving x = -7(2)

multiply -7 and 2 to get -14

x = -14

4 0
3 years ago
Read 2 more answers
In a survey 9/25 students ride the bus and 19/50 walk to school. What fraction of students ride the bus or walk?
san4es73 [151]
Well since 19/50 can't be simplified you have to double 9/25 which is 18/50 so then add 18 + 19 = 37 So 18/50 + 19/50 = 37/50 so 37/50 of the students ride the bus or walk to school.
7 0
3 years ago
Read 2 more answers
Please answer ASAP! Photo below!
Maru [420]
B


-2 1/4 = -9/4
(-9/4)/(-2/3)
7 0
3 years ago
Read 2 more answers
Micheal was asked to give examples of the identity property of addition and identity multiplication. Below are his answers.
xxMikexx [17]

Answer:

identity property of addition-

a+0=a

identity property of multiplication-

a*1=a

Step-by-step explanation:

i cant give u an exact answer as u didnt give Micheals answers so i just gave some examples about what addition and multiplication identity property should look like. Identity property's concept is to keep the same identity. Basically, "a" shouldnt change. In addition, to keep a the same all u hv to do is add 0 as anything plus 0 is the same. for multiplication, just multiply by 1. Hope this helps!!

5 0
3 years ago
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