1) Call x the sample mean = 3.56

2) Call s the sample standard deviation = 0.2

3) Given that the variable is normally distributed and the sample is large, you determine the interval of confidence from:

x +/- Z(0.5) s/√n

Wehre Z(0.5) is the value of the probabilities over 5% (90% of confidence mean to subtract 10%, which is 5% for each side (tails) of the normal distribuition) and is taken from tables.

Z(0.5) = 0.3085

Then the inteval is

x +/- 0.385 *s /√n = 3.56 +/- 0.385 * 0.2/√45

3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.

8 0

3 years ago

Question 3 of 25

lys-0071 [83]

An ordered pair of the inverse of f(x)D, (1.2)

3 0

2 years ago

The expression (4x+5)(3x-7) is the factorization of what trinomial?

RUDIKE [14]

It's easy to find the trinomial. Just multiply (4x + 5) and (3x - 7) together.

$(4x + 5)(3x - 7) = 12x^{2} - 28x + 15x - 35 = 12x^{2} - 13x - 35$

So the final answer is $12x^{2} - 13x - 35$

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5 0

2 years ago

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Given f(x) = x − 7 and g(x) = x2 . What does f(g(4)) =

Stells [14]

Answer:

Step-by-step explanation:

f(x) = x − 7

g(x) = x^2

Find g(4) = 4^2 = 16

Then find f(g(4)) = f(16) = 16 -7 = 9

3 0

2 years ago

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