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3 years ago

What is the speed, in meters per second, of a paper airplane that flies 24 meters in 6 seconds?

Mathematics

2 answers:

Tanya [424]3 years ago

8 0

Answer:

4 meter per second.

Step-by-step explanation:

To calculate speed , you need to divide 24 meters by 6 seconds.

*to calculate distance , multiply speed with time.

*to calculate speed , divide distance with time.

*to calculate time , divide distance and speed.

>~<sorry for the bad english

Rama09 [41]3 years ago

6 0

In order to find the answer to this question you will have to divide 24 and 6.

$24\div6$

$24\div6=4$

$=4$

Therefore the paper airplane flies "4 meters every second."

Hope this helps.

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Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

4 0

3 years ago

Brainly which is the distance between (-3,4) and (7,13)

Veseljchak [2.6K]

Answer:

Root 181

Step-by-step explanation:

Using distance formula, we know that the answer will be the square root of 181. Unfortunately, this is not a perfect square, and it is prime, so that number will remain the same.

Distance Formula: $\sqrt{(13-4)^{2} + (7+3})^2} = \sqrt{181}$

Hope this helped!

5 0

3 years ago

5+2x+6=x +10 <br> Solve this equation and show ur work

Rama09 [41]

Answer:

x = -1

Step-by-step explanation:

5 + 2x + 6 = x + 10

11 + 2x = x + 10

-x -x

11 + x = 10

-11 -11

x= -1

3 0

3 years ago

Read 2 more answers

Help me out please i don’t understand

Murljashka [212]

Answer:

im not 100% sure if this the answer

C=5/9F-160/9

Step-by-step explanation:

7 0

3 years ago

Write functions for each of the following transformations using function notation. Choose a different letter to represent each f

joja [24]

Answer:

1. Translation: g(x) = f(x-a)+b.

2. Reflection around y-axis: h(x) = f(-x)

3. Reflection around x-axis: k(x) = -f(x)

4. Rotation of 90° : $R_{90} (x,y)=(-y,x)$

5. Rotation of 180° : $R_{180} (x,y)=(-x,-y)$ .

6. Rotation of 270° : $R_{180} (x,y)=(y,-x)$ .

Step-by-step explanation:

Let us assume that the transformations namely translation, reflection are applied to a function f(x) and the rotation is applied to the point ( x,y ).

So, according to the options:

We know that 'translation moves the image in horizontal and vertical direction'.

1. As we have to translate the function f(x) 'a' units to the right and 'b' units up. So, the new form of the function becomes g(x) = f(x-a)+b.

Further, we know that 'reflection means to flip the image around a line'.

2. As, we have to reflect the function f(x) around y-axis. The new form of the function is h(x) = f(-x).

3. As, we have to reflect the function f(x) around x-axis. The new form of the function is k(x) = -f(x).

Since, 'rotation turns the image around a point to a certain degree'.

4. As, we have to rotate ( x,y ) counter-clockwise to 90° about the origin, the new form of the function is $R_{90} (x,y)=(-y,x)$ .

5. As, we have to rotate ( x,y ) counter-clockwise to 180° about the origin, the new form of the function is $R_{180} (x,y)=(-x,-y)$ .

6. As, we have to rotate ( x,y ) counter-clockwise to 270° about the origin, the new form of the function is $R_{180} (x,y)=(y,-x)$ .

5 0

3 years ago