Answer:
a is your answer
Step-by-step explanation:
;)
Answer:
I think A but sorry i might be wrong
Step-by-step explanation:
Answer:
When we have a rectangle of length L and width W, the area is calculated as:
A = W*L
In this case, W = x, and the area is:
A = 2*x
Then we must have L = 2.
We know that the area of the window and the frame (together) is:
a = 2*x^2 + 12*x + 16
The area of the frame alone, will be equal to the difference between the area of both objects (a) and the area of the window alone (A)
area of the frame = a - A
= (2*x^2 + 12*x + 16) - (2*x) = (2*x^2 + 10*x + 16)
This is the area of the frame
Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC=
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
It might be D in my opinion? But I probably did my work wrong.. sorry!