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Lorico [155]
3 years ago
8

Complete the table such that a and b represent a proportional relationship

Mathematics
1 answer:
pychu [463]3 years ago
7 0

Answer:

hdudhdhdbdbdhdhshshdhxe

Step-by-step explanation:

ano grade kana

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the sum of −2x2 + x + 31 and 3x2 + 7x − 8 can be written in the form ax2 + bx + c, where a, b, and c are constants. What is the
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Answer:

a+b+c=32

Step-by-step explanation:

we have

(-2x^{2} +x+31)+(3x^{2}+7x-8)

Adds the terms

Group terms that contain the same variable

(-2x^{2}+3x^{2})+(x+7x)+(31-8)

Combine like terms

(x^{2})+(8x)+(23)

where

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therefore

a+b+c=1+8+23=32

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3 years ago
Find the measure of 7
fredd [130]

Answer:

126 degree

Step-by-step explanation:

use alternate angles and linear pair

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Liz is using the distributive property to evaluate the expression 27(36) by using friendlier numbers. Her work is shown below.
Katen [24]
Liz attempted to factor 36. Since 36 = 3*12 and not 3+12, this is not the way to go. In stead of factoring 36, she should have split it into a friendly sum, like 36=30+6.

Then Step 1 should have been 27(6+30).
4 0
3 years ago
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PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of
Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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yes because you need to do this then you need to do that and plus yeah you right
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