Answer:
C. Grant Access Using Hierarchy sharing setting on the Job Object set to false.
A. "Modify All" permission for Job Object on the Delivery Profile.
E. Organization-Wide Default sharing setting of Private on the Job Object.
Explanation:
In this example, we are dealing with sensitive information. We learn that because of this, the only users who should be able to view and edit job records are the user who owns the record and all users in the delivery profile. In order to protect the information, it is necessary to have an organization-wide default sharing setting of private. After this, we also need the "modify all" permission for job object on the delivery profile and the Grant Access Using Hierarchy sharing setting to be set to false.
Answer:
B. localization of a Web site
Explanation:
Localization of a Website or Website localization is the process and procedures of familiarize and adapting an existing website to native or local language and culture in the target market. It is the method of adapting a website into a special linguistic and cultural environment which is much more robust than just the simple translation of text.
Answer:d) Quantitative data
Explanation: Quantitative data is the data that is required for the measurement of count and then exhibited in the numeric values.It is expressed through the type of name, number,code, symbol etc. It is used in the questionnaire, surveys, interviews etc.
Other options are incorrect because time series data is data according to the time event and categorical data is based on the categories of event.Thus, the correct option is option(d).
Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.
