Answer:
- 15 mL of 100% vinegar
- 45 mL of Italian dressing
Step-by-step explanation:
Let v represent the amount of 100% vinegar to be included in the mixture. Then the amount of vinegar in the overall mixture is ...
1.00v + 0.08(60 -v) = 0.31(60)
0.92v = 60(0.23) . . . . . . . collect terms, subtract .08(60)
v = 60(0.23/0.92) = 15 . . . mL of vinegar
60 -v = 45 . . . mL of dressing
15 mL of vinegar and 45 mL of Italian dressing should be used.
Answer:
5 terms
to the fourth degree
leading coeff of 1
3 turning points
end behavior (when x -> inf, y -> inf. When x -> - inf, y -> -inf)
x intercepts are (0,-4) (0,-2) (0,1) (0,3)
Relative min: (-3.193, -25) (2.193, 25)
Relative max: (-0.5, 27.563)
Step-by-step explanation:
The terms can be counted, seperated by the + and - in the equation given.
The highest exponent is your degree.
The number before the highest term is your leading coeff, if there is no number it is 1.
The turning points are where the graph goes from falling to increasing or vice versa.
End behaviour you have to look at what why does when x goes to -inf and inf.
X int are the points at which the graph crosses the x-axis.
The relative min and max are findable if you plug in the graph on desmos or a graphing calculator.
Step-by-step explanation:
(i). a+(b+c) = (a+b)+c
-35+(10-5) = (-35+10)+(-5)
-35+5 = -25-5
-30 = -30
(ii). a×(b+c) = a×b + a×c
-35 × [10+(-5)] = -35×10 + -35×-5
-35 × (10-5) = -350 + 175
-35 × 5 = -350 + 175
-175 = -175
Answer: There is a probability of 0.05 that there is neither truck is available.
Step-by-step explanation:
Since we have given that
Probability that the first truck is available = 0.75
Probability that the second truck is available = 0.50
Probability that both trucks are available = 0.30
So, probability that either first truck or second truck is available is given by

We need to find the probability that neither truck is available.
so, P(A∪B)'=1-P(A∪B)

Hence, there is a probability of 0.05 that there is neither truck is available.
C, B, G common vortex ( B) and common side (C, G)