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Dovator [93]
3 years ago
7

Y = 2x + 4 2x - y = -6

Mathematics
1 answer:
Stella [2.4K]3 years ago
7 0

no solution b/c

2x-2x+4= -6

0+4= -6

4= -6

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9-g&gt;3;g=5<br> Solution of the inequality
NARA [144]
<span><span>9−5</span>>3</span><span><span>4></span>3

</span><span>True hope i helped</span>
8 0
4 years ago
A parallelogram has a base of 100, a side length of 36, and interior angle of 60, what is the height
koban [17]

Answer:

18\sqrt{3}

Step-by-step explanation:

Please see the attached image

I'm assuming you've already learned the special properties of a 30-60-90 triangle.

By drawing a 30-60-90 triangle by constructing line BC, and using the special proportions that come from it, we can find that

AB=AC/2=36/2=18

and

BC=AB*\sqrt{3}=18\sqrt{3}

8 0
3 years ago
Find an equation for the line that passes through the points (-5,-5) and (1,4)
Andreas93 [3]

The general line through (a,b) and (c,d) is

(c-a)(y-b)=(d-b)(x-a)

Here that's

(1 - - 5)(y - - 5) = (4 - -5)(x - - 5)

6(y+5)=9(x+5)

6y + 30 = 9x + 45

-15 = 9x - 6y

3x - 2y = -5

Answer: 3x - 2y = -5

We could put that in slope intercept form,

2y = 3x + 5

y = (3/2) x + 5/2

Answer: y = (3/2) x + 5/2

3 0
4 years ago
What is the y-coordinate for the solution to the system of equations? {−x+3y=9 {y=2/3x
shusha [124]

Answer:

y = 6

Step-by-step explanation:

3 y - x = 9

y = (2 x)/3

Substitute y = (2 x)/3 into the first equation:

{x = 9

y = (2 x)/3

Substitute x = 9 into the second equation:

Answer:

x = 9

y = 6

7 0
3 years ago
An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile the width of the lake is 1/5 the length of
DIA [1.3K]
Answer:  The dimensions are:   " 1.5 mi.  ×  ³⁄₁₀  mi. " .
_______________________________________________
             { length = 1.5 mi. ;  width =  ³⁄₁₀  mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:

A = L * w ; 

in which:  A = Area = (9/20) mi.² ,
                L = Length = ?
                w = width = (1/5)*L = (L/5) = ?
________________________________________
  A = L * w ;  we want to find the dimensions; that is, the values for
                         "Length (L)"  and "width (w)" ; 
_______________________________________
Plug in our given values:
_______________________________________
 (9/20) mi.² = L * (L/5) ;  in which: "w = L/5" ; 
 
     → (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
   
          ↔  L² / 5  = 9/20 ;
 
            →  (L² * ? / 5 * ?) = 9/20 ?    

                →     20÷5 = 4 ;  so; L² *4 = 9 ;
 
                   ↔    4 L² = 9 ; 
 
                   →  Divide EACH side of the equation by "4" ;
           
                   →   (4 L²) / 4 = 9/4 ;
______________________________________
           to get:  →  L² = 9/4 ; 
 Take the POSITIVE square root of each side of the equation; to isolate "L" on one side of the equation; and to solve for "L" ;
___________________________________________          
 
     →   ⁺√(L²)   =   ⁺√(9/4) ;

    →   L  =  (√9) / (√4) ; 

    →  L = 3/2 ; 

    → w = L/5 = (3/2) ÷ 5 = 3/2 ÷ (5/1) = (3/2) * (1/5) = (3*1)/(2*5) = 3/10;
________________________________________________________
Let us check our answers:
_______________________________________
(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??

→ (3/2)mi. * (3/10)mi.  =  (3*3)/(2*10) mi.² = 9/20 mi.² ! Yes!
______________________________________________________
So the dimensions are: 

Length = (3/2) mi. ;  write as: 1.5 mi.

width = ³⁄₁₀ mi.
___________________________________________________
or; write as:  " 1.5 mi.  ×  ³⁄₁₀ mi. " .
___________________________________________________
7 0
3 years ago
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