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2 years ago

HELP PLZZZZZZZZZZZZZZZZZZZZ

Mathematics

1 answer:

allochka39001 [22]2 years ago

7 0

Step-by-step explanation:

it 90 the sec one

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Find the square of ( b - 9 )

Kruka [31]

Answer:

${b}^{2} - 18b + 81$

Step-by-step explanation:

${(b - 9)}^{2} = {b}^{2} - 2 \times b \times 9 + {(9)}^{2} \\ = {b}^{2} - 18b + 81$

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2 years ago

What is 5/7 / 2/7.. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

netineya [11]

Answer:

I think the answer may be 0.05.

Step-by-step explanation:

This may be incorrect, but I hope it helps ^-^

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2 years ago

Read 2 more answers

4 - 3y = 31 what does y equal?

34kurt

Here’s your answer:

Y=-9

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2 years ago

$700 at 8% for 6 years

Elenna [48]

It could mean
1. simple interest
2. compound interest

1.simple interest
so just 8% of that 700 is added on
find 8% of 700
8% of 700=0.08 times 700=0.56
6 years=0.56 times 6=3.36
add
3.36+700=703.36

2. compound interst

that means the each year, it gives you 8% on that new thing
so
8%=0.08
so each year, it is multiplied by 1.08 since you add the original (1) to the 8% 0.08
so
6 years means
700 times 1.08^6=700 times 1.08 times 1.08 times 1.08 times 1.08 times 1.08 times 1.08=1110.81

answers are
if simple interest=$703.36
if compound interst=$1110.81

3 0

3 years ago

The mean number of hours per day spent on the phone, according to a national survey, is four hours, with a standard deviation of

Reika [66]

Answer:

The new mean is 5.

The new standard deviation is also 2.

Step-by-step explanation:

Let the sample space of hours be as follows, S = {x₁, x₂, x₃...xₙ}

The mean of this sample is 4. That is, $\bar x=\frac{x_{1}+x_{2}+x_{3}+...+x_{n}}{n}=4$

The standard deviation of this sample is 2. That is, $s=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}=2$ .

Now it is stated that each of the sample values was increased by 1 hour.

The new sample is: S = {x₁ + 1, x₂ + 1, x₃ + 1...xₙ + 1}

Compute the mean of this sample as follows:

$\bar x_{N}=\frac{x_{1}+1+x_{2}+1+x_{3}+1+...+x_{n}+1}{n}\\=\frac{(x_{1}+x_{2}+x_{3}+...+x_{n})}{n}+\frac{(1+1+1+...n\ times)}{n}\\=\bar x+1\\=4+1\\=5$

The new mean is 5.

Compute the standard deviation of this sample as follows:

$s_{N}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{n-1}\sum ((x_{i}+1)-(\bar x+1))^{2}\\=\frac{1}{n-1}\sum (x_{i}+1-\bar x-1)^{2}\\=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=s$

The new standard deviation is also 2.

5 0

3 years ago