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lidiya [134]
3 years ago
8

A file is currently compressed in its local file system. For security reasons, the file is required to be encrypted. The file ca

n be both compressed and encrypted. True or False
Computers and Technology
1 answer:
skelet666 [1.2K]3 years ago
3 0
True. An encryption scheme doesn't care what it is encrypting, be it compressed or uncompressed.

Note that an encrypted file will look like random data to most compression algorithms, so it makes sense to first compress, then encrypt, to get the maximum efficiency from the compression.
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Win10如何删除自己添加的环境变量?...............
Paha777 [63]

Answer:

方法/步骤

右键单击以选择此计算机,然后有一个菜单来选择属性。

选择后,打开属性面板以找到我们的高级系统设置。

打开后,我们在系统设置下找到高级设置。

打开后,我们看到下面有一个环境变量选项。

打开后,我们在右下角看到一个删除选项。

单击删除到,在右下角后单击删除,然后单击确定的选项。 ...

本文未经授权摘自百度经验

8 0
2 years ago
5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S
Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0
3 years ago
In 1-2 sentences, describe how you would open a new word processing document.
Gennadij [26K]
This depends on what computer and
System it's running on
4 0
3 years ago
A university wants to schedule the classrooms for final exams. The attributes are given below:
iVinArrow [24]

Answer:

See explaination

Explanation:

Clearly the entities are as follows:-

Course

Section

Room

Test

The relationship among entities are as follows:-

Course has Section

Test is conducted for Course

Test is conducted in Section

Test is conducted in Room

Attributes of each entities are as follows:-

Course (CourseID, Name, Department)

Section (SectionID, Enrollment)

Room (RoomNumber, Capacity, Building)

Test (Time)

Section is a week entity as, there may be same sections for different courses, therefore section uses the primary key of course entity as foreign key.

Also entity Test is dependent upon the entities Room,Section and Course, therefore primary keys of these entities will be used as foreign key in the Test entity.

Check attachment for the ER diagram

5 0
3 years ago
A light rag is striking the surface of earth. Which factor would make the light ray more likely to be absorbed than reflected?
Sergeu [11.5K]

Answer:

The answer is D.

Explanation:

because the other answers doesn't make sense.

6 0
3 years ago
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