To get the solution, we are looking for, we need to point out what we know.
1. We assume, that the number 45.5 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 45.5 is 100%, so we can write it down as 45.5=100%.
4. We know, that x is 6.81% of the output value, so we can write it down as x=6.81%.
5. Now we have two simple equations:
1) 45.5=100%
2) x=6.81%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
45.5/x=100%/6.81%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 6.81% of 45.5
45.5/x=100/6.81
(45.5/x)*x=(100/6.81)*x - we multiply both sides of the equation by x
45.5=14.684287812041*x - we divide both sides of the equation by (14.684287812041) to get x
45.5/14.684287812041=x
3.09855=x
x=3.09855
now we have:
6.81% of 45.5=3.09855
Hope this helps!
Answer:
Step-by-step explanation:
Hhhh
Answer:
Step-by-step explanation:
If the Number of Sales of x units, N(x) is defined by the function:
![N(x)=-5x^3+235x^2-3400x+20000,10\leq x\leq 40](https://tex.z-dn.net/?f=N%28x%29%3D-5x%5E3%2B235x%5E2-3400x%2B20000%2C10%5Cleq%20x%5Cleq%2040)
![N'(x)=-15x^2+470x-3400\\When -15x^2+470x-3400=0\\x=20, x=11\frac{1}{3}](https://tex.z-dn.net/?f=N%27%28x%29%3D-15x%5E2%2B470x-3400%5C%5CWhen%20-15x%5E2%2B470x-3400%3D0%5C%5Cx%3D20%2C%20x%3D11%5Cfrac%7B1%7D%7B3%7D)
Next, we text the critical points and the end points of the interval to see where the derivative is increasing.
![N'(10)=-200\\N'(11\frac{1}{3})=0\\N'(19)=115\\N'(20)=0\\N'(40)=-8600](https://tex.z-dn.net/?f=N%27%2810%29%3D-200%5C%5CN%27%2811%5Cfrac%7B1%7D%7B3%7D%29%3D0%5C%5CN%27%2819%29%3D115%5C%5CN%27%2820%29%3D0%5C%5CN%27%2840%29%3D-8600)
Thus, the rate of change of sales
is increasing in the interval
on 10≤x≤40.
Answer:
13.708
Step-by-step explanation:
I think it’s 0.5, sorry if it’s wrong