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DerKrebs [107]
3 years ago
10

A bus​ averages 8 miles per hour faster than a trolley. If the bus travels 60 miles in the same time it takes the trolley​ to tr

avel 44 miles, then what is the speed of each
Mathematics
1 answer:
hammer [34]3 years ago
3 0

Answer:

Bus speed:  22 mph; Trolley speed:  14 mph

Step-by-step explanation:

Let rb represent the speed of the bus and rt the speed of the trolley.  Then rb = rt + 8 (mph).

Recall that distance = rate times time.  Two different distances and two different speeds are involved here, but only one time.

Thus,

             60 mi                                                           44 mi

     --------------------- = time (same in both cases) = -------------

          rt + 8 mi/hr                                                        rt

Cross-multiplying, we get   44rt + 8(44) = 60 rt, or

                                                    352 = 16rt.

Solving this for rt, we get    rt = speed of bus = 352/16 = 22 mph

The speed at which the bus travels is 22 mph and that at which the trolley travels is (22 mph - 8 mph) = 14 mph

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Answer:

9 hours

Step-by-step explanation:

455/7 gives you the mph

which is 65

then divide 585 miles by the mph (65)

585/65

= 9 hours

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Can anybody please answer question 6
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Answer:

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Step-by-step explanation:

its not that hard

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3 years ago
A) 120 is what percentage of 30
scZoUnD [109]

Answer:

a ) 400 percent

b )  n = 25

c)  n= 36

Step-by-step explanation:

Is means equals, of means multiply and percents need to be changed to decimals.

a) 120 is what percentage of 30

120 = P * 30

Divide each side by 30

120/30 =P* 30/30

4 = P

Multiply by 100 to give the percentage

4 * 100

400 percent


b) 30 is 120% of what number

30 = 1.2 * n

Divide each side by 1.2

30/1.2 = 1.2n/1.2

25  = n


c) what number is 30%of 120

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n =36


3 0
3 years ago
Read 2 more answers
The angles formed by two perpendicular lines have a measure of _______.
Tpy6a [65]
The answer is 90 degrees. SO it would be B
7 0
3 years ago
Read 2 more answers
Someone please help or i’ll be failing geometry this year
Vlad [161]

Step-by-step explanation:

I don't know what constructions you were taught.

a "similar" triangle is a triangle with exactly the same angles as the other triangle, but the lengths of all sides are stretched or shortened by the same scaling factor f.

by saying 1:2 she means the second triangle should have sides with twice the lengths of the first triangle (f=2).

and the extra challenge - same basic thing. she allows you to pick one of the two triangles as reference. and then you need to draw a third triangle (again with the same angles) with the side lengths extended by the scaling factor f of 4/3.

I would draw the triangles right on top of each other with the same starting corner (let's call it A) for all 3.

we would get the triangles ABC, AMN and AXY.

the points B and C would be then halfway on AM and AN.

and M and N would then a bit before X and Y on AX and AY.

the beauty is, you only need to construct 2 sides of every new triangle down to the new endpoints. the third side is automatically scaled correctly, and you only need to connect these new endpoints.

let's assume you draw a triangle (just very simple) ABC with all side lengths being 3. so, AB=3, AC=3, BC=3.

now you draw AMN by extending AB and AC to a side length of 6 (f=2) creating M and N, and you connect M and N.

and then you can create the third triangle AXY by extending AM and AN by a factor of 4/3 to side lengths of 8 (4/3 × 6 = 8) creating new end points X and Y. and you connect X and Y.

and that is it. all 3 triangles are similar (the same angles), and all sides of a triangle have the same length ratio to the sides of the other triangle(s).

4 0
3 years ago
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