Question

Triangle A'B'C' is formed using the translation (x + 2 y + 0) and the dilation by a scale factor of 1/2 from the origin. Which equation explains the relationship between
AB and A"B"?

Answer 1

Answer:

$A"B" = \frac{AB}{2}$

Step-by-step explanation:

Given

$k = \frac{1}{2}$ --- scale factor

Required

Relationship between AB and A"B"

$k = \frac{1}{2}$ implies that the sides of A"B"C" are smaller than ABC

i.e.

$A"B" = k * AB$

$A"B" = \frac{1}{2} * AB$

This gives:

$A"B" = \frac{AB}{2}$