Answer:
68 ≥ t ≤ 770
Step-by-step explanation:
First picture:
2 and 7 are alternate exterior angles, which when added together need to equal 180 degrees.
Angle 7 = 180 - 146 = 34
Answer is B.34
Second picture:
Angle 8 = 48
Angle 8 + angle 7 = 180
Angle 7 = 180 - 49 = 131
Angle 5 and angle 7 are vertical angle, so angle 5 = angle 7 = 131
Angle 6 is a vertical angle to angle 8 so = 49
Angle 1 = angle 5 = 131
Angle 2 = angle 6 = 49
Angle 3 = angle 7 = 131
Angle 4 = angle 8 = 49
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!