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Katena32 [7]
4 years ago
10

YO PLZ HELP ASAP!!! MARKIN BRAINIEST!!!

Mathematics
1 answer:
aivan3 [116]4 years ago
6 0

Hello!

The first question is looking for the vertex form of a quadratic. From the vertex form, you can find the extreme value of the equation, or the vertex.

Vertex form is defined as y = a(x - h)² + k, where (h, k) is the vertex.

To convert to vertex form, first use the distributive property to take out the 3 from the first two terms.

y = 3x² + 30x + 71

y = 3(x² + 10x) + 71

Now, complete the square for the equation inside the parenthesis. This can be done by seeing which number makes a perfect binomial. Remember that you must multiply it by 3 as there is the 3 outside the parenthesis.

y + 75 = 3(x² + 10x) + 75 + 71

y + 75 = 3(x² + 10x) + 3(25) + 71

y + 75 = 3(x² + 10x + 25) + 71

y = 3(x² + 10x + 25) - 4

And then, turn the equation into a perfect square binomial.

y = 3(x + 5)² - 4

Now you have your vertex form.

Looking at the values, -5 is h and -4 is k (as recall in the original equation, you are subtracting h and adding k).

Therefore, the vertex is (-5, -4).

Hope this helped!

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Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
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