are you sure you wrote that right?????
Make the denominators the same number. Then do the problem as you would regularly without fractions
1)
log 98 = log( 7 * 14 ) = log 7+ log 14= h + j ;
2)
log 175 = log ( 5^2 * 7 ) = log 5 ^ 2 + log 7 = 2 * log 5 + log 7 = 2i + h ;
3)
log 2 = log ( 14 / 7 ) = log 14 - log 7 = j - h ;
4)
log 245 = log ( 7^2 * 5 ) = log 7 ^2 + log 5 = 2 * log 7 + log 5 = 2h + i ;
Answer:
(x, y) = (2, 4) or (-1, 1)
Step-by-step explanation:
y = x^2
y = x + 2
=> x^2 = x + 2
Transfer all terms to the left, we have:
=> x^2 - x - 2 = 0
Perform some modifications, we have:
=> x^2 + x - 2x - 2 = 0
Let's group the left-side terms up.
=> x(x + 1) - 2(x + 1) = 0
=> (x - 2)(x + 1) = 0
=> x = 2 => y = x + 2 = 2 + 2 = 4
=> x = -1 => y = x + 2 = -1 + 2 = 1
=> Solution is (x, y) = (2, 4) or (-1, 1)
Hope this helps!
